Question

A room has an area of 60 square meters and a perimeter of 32 meters. What are the length and width of the room?

Answer 1

6 and 10

Explanation:

xy=60

2(x+y)=32

x+y=16

y=16-x

Substitute y into area equation

x(16-x)=60

16x-x^2=60

x^2-16x+60=0

(x-10)(x-6)=0

x=10, 6

y=6, 10