Question

Suppose that the pressure of 1.00L of gas is 500mmHg when

the temperature is 200K. At what temperature is the Volume 2.00L
and the pressure 0.750 atm?

Answer 1

456 K

Step-by-step explanation:

PV = nRT

PV/ T = nR since nR is constant for this scenario

P1 V1 /T1 = P2 V2 / T2

500 * 1 / 200 = (760*.75) *2 /T2 Solve for T2 =456 K

(Note that .750 atm = 760 mmHg * .75 )