Answer:
Profit-maximizing price = $300
People on flight = 200 people per flight
Profit for each flight = $10,000
Step-by-step explanation:
As per the data given in the question,
Demand curve in inverse form:
P = 500 - Q
We know that marginal revenue curve for a linear demand curve will twice the slope,
So Marginal Revenue= 500 - 2Q
Marginal cost of carrying per passenger = $100
To determine profit maximizing quantity, Equating Marginal Revenue to Marginal Cost
Let the people on each flight be Q, then
500 - 2Q = 100
Q = 200 people per flight
Substituting the value Q in demand equation to find profit maximizing price for each ticket
Profit Maximizing price (P) = $500 - $200
= $300
Profit for each flight = Total Revenue - Total Cost
= (300) (200) - (30,000 + (200) (100) )
= $10,000 per flight