Answer:
a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15
Alternative hypothesis: H₁: The proportion of defective item of computer
has been higher. That is P> 0.15 (Right tailed test)
b) Test statistic

c) Calculate the value of the test statistic = 0.991
d) The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57
e) Null hypothesis accepted at 0.01 level of significance
f) we accepted null hypothesis.
Hence the proportion of defective item of computer has been lowered.
Explanation:
Step(i):-
Given the sample size 'n' = 42
Given random sample of 42 computers were tested revealing a total of 4 defective computers.
The defective computers 'x' = 4
The sample proportion of defective computers

Given The Population proportion 'P' = 0.15
The level of significance ∝=0.01
Step(ii):-
a) Null hypothesis : H₀: the proportion of defective item of computer has been lowered. That is P < 0.15
Alternative hypothesis: H₁: The proportion of defective item of computer
has been higher. That is P> 0.15 (Right tailed test)
b)
Test statistic

c)

Calculate the value of the test statistic Z = - 0.9991
|Z| = |- 0.9991| = 0.991
Step(iii):-
d)
The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57
e) Calculate the value of the test statistic Z = 0.991 < 2.57 at 0.01 level of significance.
Conclusion:-
Hence the null hypothesis is accepted at 0.01 level of significance.
f)
The proportion of defective item of computer has been lowered.