Question

Use the basic probability principle to solve the following problem. Express each probability as a fraction reduced to lowest terms. A​ 12-sided die is rolled. The set of​ equally-likely outcomes is StartSet 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 comma 11 comma 12 EndSet . Find the probability of rolling any number except 10.

Answer 1

`(11)/(12)`

Explanation:

If a 12-Sided die is rolled. The set of​ equally-likely outcomes is:

{1,2,3,4,5,6,7,8,9,10,11,12}

`\text{The probability of rolling a 10}=(1)/(12)`

Therefore, the probability of rolling any number except 10 is:

`\text{The probability of rolling a number except 10}\\=1-\text{The probability of rolling a 10}\\=1-(1)/(12)\\=(11)/(12)`