Question

Arrange the following events for the synthesis of RNA in the correct order: Nucleophilic attack of the 3′ OH group of the first nucleotide at the α-phosphate group of the second nucleotide 5′ triphosphate occurs. Template specific rNTPs are bound. Several DNA bases are unwound, forming a stable complex. Polymerase finds a promoter region. A Mg+2-dependent isomerization of DNA takes place.

Answer 1

4, 3, 5, 2, 1

Step-by-step explanation:

The process of syhthesis of protein is called trancription.

• The proces sf transcription begin with the binding of RNA polymerase enzyme with a sequence of DNA called the promoter.
• RNA polymerase allows the unwinding of DNA bases forming a stable complex.
• In the next step, a Mg2+-dependent isomerization occurs, that produces a modified form of the open- promoter complex.
• RNA polymerase has one nucleoside triphosphate binding site which helps during elongation and binds any of the four common ribonucleoside triphosphates (rNTPs).
• Then a nucleophilic attack of the 3' hydroxyl (OH) present at the first nucleotide on the a - phosphorus gorup of the second nucleotide 5' triphosphate occurs that forms the first phosphodiester bond.

Hence, the correct order is 4, 3, 5, 2, 1.