Question

If you have 3kg of lead and put 3840 joules of heat energy into that mass of lead. Taking

careful measurements, you observe the temperature of the lead rise from 40C to 50C.
What is the specific heat capacity of lead?

Answer 1

Answer : The specific heat capacity of lead is,
`0.128J/g^oC`

Explanation :

Formula used:

`q=m* c* (T_2-T_1)`

where,

q = heat produced = 3840 J

m = mass of lead = 3 kg = 3000 g

c = specific heat capacity of lead = ?

`T_1` = initial temperature =
`40^oC`

`T_2` = final temperature =
`50^oC`

Now put all the given values in the above formula, we get:

`3840J=3000g* c* (50-40)^oC`

`c=0.128J/g^oC`

Therefore, the specific heat capacity of lead is,
`0.128J/g^oC`