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a uniform disc and hollow right circular cone have the same formula for their moment of inertia when rotating about the central axis why is it so?

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Answer:

This is as a result that about the central axis a collapsed hollow cone is equivalent to a uniform disc

Step-by-step explanation:

The integration of the differential mass of the hollow right circular cone yields


I=\int\limits dmr^2 = \int\limits^a_b {(2Mxr^2)/(R^2 +H^2) } \, dx = (2MR^2dx)/((R^2 +H^2)^2) ((R^2 +H^2)^2)/(4) = (1)/(2)MR^2

and for a uniform disc

I = 1/2πρtr⁴ = 1/2Mr².

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