Help please acids and basis

ChenHao Wu asked Sep 3, 2023

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14 votes

ChenHao Wu asked Sep 3, 2023

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21 votes

Let's see

$\\ \rm\Rrightarrow pOH=-log[OH-]$

$\\ \rm\Rrightarrow pOH=-logx$

$\\ \rm\Rrightarrow 4.86=-logx$

$\\ \rm\Rrightarrow logx=-4.86$

$\\ \rm\Rrightarrow x=10^(-4.86)$

$\\ \rm\Rrightarrow x=1.38M$

Ashitosh answered Sep 7, 2023

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