Question

Tomás ran 6 1/2 kilometers, Jackie ran 8,000 meters, Joseph ran 5.9 kilometers,

Mai Yee ran 2,790 meters. Sarita ran farther than 2 of the people in the table and slower than the others. How far could sarita have ran. Explain how you found your answer.

Answer 1

5900 meters < Sarita < 6500 meters

Explanation:

Given

Tomás =
`6(1)/(2) km`

Jackie = 8,000 m

Joseph = 5.9 km

Mai Yee = 2,790 m

Where km and m represent kilometers and meters respectively

Required

How far could Sarita have ran

First, we'll convert the distance covered by each individuals to one units (Preferably meters)

We'll need to convert distance covered by Tomás and Joseph because they're given in kilometers.

Since 1 km = 1000 m, then we have

Tomás =
`6(1)/(2) km`

Tomás =
`6(1)/(2) * 1000 m` (Convert fraction to decimal)

Tomás =
`6.5 * 1000 m`

Tomás = 6500 m

Joseph = 5.9 km

Joseph = 5.9 * 1000 m

Joseph = 5900 m

Now that we have the same unit all through, the next step is to list them out

Tomás = 6500 m

Jackie = 8,000 m

Joseph = 5900 m

Mai Yee = 2,790 m

Then, we rearrange in ascending order (from smallest to biggest)

Mai Yee = 2,790 m

Joseph = 5900 m

Tomás = 6500 m

Jackie = 8,000 m

The condition given in the question is that Sarita ran farther than 2 of the people in the table and slower than the other 2

This means that Sarita ran farther than the least 2 "Mai Yee and Joseph"

And at the same time Sarita covered lesser distance than the highest 2 "Tomás and Jackie"

This means that distance covered by Sarita is greater than distance covered by Joseph and less than distance covered by Tomás

Since no option is given, I'll represent the answer using inequality

Recall that

Joseph = 5900 m

Tomás = 6500 m

Sarita could have ran a distance greater than 5900 meters and less than 6500 meters

Distance covered by Sarita: 5900 < Sarita < 6500