Question

At 5 atmospheres of pressure and 70oC, how many moles are present in 1.5 L of O2 gas?

Answer 1

0.27 mol

Step-by-step explanation:

Given data

• Pressure (P): 5 atm

• Temperature (T): 70°C

• Volume (V): 1.5 L

• Moles of O₂ (n): ?

Step 1: Convert the temperature to the Kelvin scale

When working with gases, we need to convert all temperatures to the absolute scale, using the following expression.

`K = \° + 273.15\\K = 70 + 273.15 = 343 K`

Step 2: Calculate the moles of gaseous oxygen

We will apply the ideal gas equation.

`P * V = n * R * T\\n = (P * V)/(R * T) = (5 atm * 1.5 L)/((0.0821atm.L)/(mol.K) * 343 K) = 0.27 mol`