Answer:
y = 2e^[2(1 - t)]
Explanation:
1/y . dy = -2. dt
ln(y) = -2t + c
ln(2) = -2(1) + c
c = 2 + ln(2)
ln(y) = -2t + ln(2) + 2
ln(y) - ln(2) = 2 - 2t
ln(y/2) = 2 - 2t
y/2 = e^(2 - 2t)
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