Register
What is the diameter of a circle with the equation (x + 6)2 + (y − 4)2 = 16?
230k views
3 votes
What is the diameter of a circle with the equation (x + 6)2 + (y − 4)2 = 16?

User Dehumanizer
by
4.5k points

1 Answer

4 votes

Answer:

8 units

Explanation:


{(x + 6)}^(2) + {(y - 4)}^(2) = 16 \\ {(x + 6)}^(2) + {(y - 4)}^(2) = {4}^(2) \\ equating \: it \: with \\ {(x - h)}^(2) + {(y - k)}^(2) = {r}^(2) \\ {r}^(2) = {4}^(2) \implies \: r = 4 \\ d = 2r = 2 * 4 = 8 \: units

Hence, diameter of the circle is 8 units.

User Gaetano Mendola
by
4.5k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.5m questions

5.9m answers

Other Questions

point P is located at (-2, 7), and point R is located at (1, 0). find the y value for the point Q that is located 2/3 the distance from point P to point R
Which of the following angles can be used to evaluate cot(-210)
Which of the following is a polynomial with roots 4, -5, and 7? A. f(x) = x^3 - 6x - 27x + 140 B. f(x) = x^3 - 6x - 20x + 27 C. f(x) = x^3 - 20x^2 - 27x + 35 D. f(x) = x^3 - 20x^2 - 35x + 140
ten granola bars and 12 bottles of water cost $23. 5 granola bars and four bottles of water cost $10. how much do one granola bar in one bottle of water cost?
If the equation y=mx+b is used to model a quantity y as a function of the quantity x, why is b considered to be the starting value?
Link Copied!