Question

What is the diameter of a circle with the equation (x + 6)2 + (y − 4)2 = 16?

Answer 1

8 units

Explanation:

`{(x + 6)}^(2) + {(y - 4)}^(2) = 16 \\ {(x + 6)}^(2) + {(y - 4)}^(2) = {4}^(2) \\ equating \: it \: with \\ {(x - h)}^(2) + {(y - k)}^(2) = {r}^(2) \\ {r}^(2) = {4}^(2) \implies \: r = 4 \\ d = 2r = 2 * 4 = 8 \: units`

Hence, diameter of the circle is 8 units.