Question

The equation x^2 + 10x = 14 has been rewritten in the form (x + p)^2= q . What is the

value of q?

Answer 1

q = 39

Explanation:

`{x}^(2) + 10x = 14 \\ {x}^(2) + 2.5.x = 14 \\ {x}^(2) + 10x + {5}^(2) = 14 + {5}^(2) \\ (x + 5)^(2) = 14 + 25 \\ {(x + 5)}^(2) = 39 \\ equating \: it \: with \\ (x + p) ^(2) = q \\ we \: find : \\ \huge \red{ \boxed{q = 39}}`