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The fuel used in many disposable lighters is liquid butane, C4H10

C
4
H
10
. Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 3.50 g
g
of butane?

User Rgtk
by
5.8k points

1 Answer

3 votes

Answer:

1.45 *10^23 atoms C

Step-by-step explanation:

3.50 g butane * 1 mol butane/58.1 g butane =0.06024 mol butane

in 1 mol C4H10 -------- 4 mol C

in 0.06024 mol C4H10 -------- 4*0.6024 = 0.241 mol C

0.241 mol C * 6.02*10^23 atoms C/1 mol C = 1.45 *10^23 atoms C

User Davidaap
by
6.3k points