Question

Two farmhouses A and B are 10.3 km apart. A third farmhouse C is located such

that angle A=83◦ and angle B=59◦. How far is C from A?

Answer 1

Distance between A to C is 16.62km

Explanation:

See attached document to get a better illustration of the angle.

A = 83°

B = 53°

C = ?

180° = 83° + 53° + C (sum of angles in a triangle is equal to 180°)

180° = 142° + c

C = 180 - 142

C = 38°

To find the distance AC, we have to use sine rule.

a / sin(A) = b / sin(B) = c / sin(C)

a / sin(A) = c / sin(C)

a /sin83 = 10.31 / sin38

Cross multiply

10.31 * sin83 = a * sin38

10.23 = (0.61566)a

a = 10.23 / 0.61566

a = 16.616 km

a = 16.62km

The distance between A and C is 16.62km