Question

What is the Molarity of the Sulfate ion in a 2M K2SO4 solution?

Answer 1

Answer: The Molarity of the sulphate ion in a 2M
`K_2SO_4` solution is 2M

Step-by-step explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n* 1000)/(V_s)`

where,

n= moles of solute

`V_s` = volume of solution in ml

`K_2SO_4\rightarrow 2K^(+)+SO_4^(2-)`

Now as 1 mole of
`K_2SO_4` gives = 1 mole of
`SO_4^(2-)`

2 moles of
`K_2SO_4` gives =
`(1)/(1)* 2=2` moles of
`SO_4^(2-)`

Thus Molarity of the sulphate ion in a 2M
`K_2SO_4` solution is 2 M