Question

A 24.8 cm tall object is placed in

front of a lens, which creates a
-3.09 cm tall image. If the object is
37.5 cm from the lens, what is the
image distance?

Answer 1

Image distance, v = 4.67 cm

Step-by-step explanation:

We have,

Height of the object, h = 24.8 cm

Height of the formed image, h' = -3.09 cm

Object distance, u - -37.5 cm

It is required to find the image distance. Lens formula is :

`(1)/(v)-(1)/(u)=(1)/(f)`

Using formula of magnification,

`m=(v)/(u)=(h')/(h)`

v is image distance

`v=(uh')/(h)\\\\v=(-37.5* (-3.09))/(24.8)\\\\v=4.67\ cm`

So, the image distance is 4.67 cm.