Answer:
59.6 g
Step-by-step explanation:
4Li + O₂ → 2Li₂O
32.0 g O₂ × (1 mol O₂ / 32.0 g O₂) = 1.00 mol O₂
1.00 mol O₂ × (2 mol Li₂O / mol O₂) = 2.00 mol Li₂O
2.00 mol Li₂O × (29.8 g Li₂O / mol Li₂O) = 59.6 g Li₂O
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