10 grams CH10 + excess O2 → ? grams CO2 + H2O

asked Aug 23, 2023 107k views

7 votes

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8 votes

Answer:

20 gm CO2

Step-by-step explanation:

CH10 mole weight = ~ 22 gm

each 22 gm CH10 produces 44 gm CO2

44 / 22 = x / 10 = 20 gm

Musooff answered Aug 30, 2023

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