22.3k views
5 votes
The measure of arc BD is __.

The measure of arc ADB is __.
The measure of arc ABC is __.

PLEASE HELP. URGENT!! ASAP

The measure of arc BD is __. The measure of arc ADB is __. The measure of arc ABC-example-1

2 Answers

0 votes

Answer:

BD= 100

ADB= 220

ABC= 180

User Karl Anderson
by
7.3k points
5 votes

- The measure of arc
\( BD \) is 260°.

- The measure of arc
\( ADB \) should be 320° (corrected).

- The measure of arc
\( ABC \) is 80°.

To find the measure of each arc in the circle, we need to remember that the total degrees in any circle is 360°. The diagram shows a circle with specific arcs and angles labeled.

Here are the steps to find each arc's measure:

1. Measure of arc
\( BD \):

- Arc
\( BD \) is opposite the central angle
\( \angle BRD \), which is not directly given.

- Since
\( \angle BRC \) is 40° and
\( \angle CRD \) is 60°, then
\( \angle BRD = 360° - (\angle BRC + \angle CRD) \).

- Calculating
\( \angle BRD \) gives
\( 360° - (40° + 60°) = 260° \).

- Therefore, the measure of arc \( BD \) is 260°.

2. Measure of arc
\( ADB \):

- Arc
\( ADB \) includes arcs
\( AD \) and
\( DB \).

- We already know
\( DB \) is 260°.

-
\( AD \) is opposite the central angle
\( \angle ARD \), which is given as 120°.

- Adding them together, the measure of arc
\( ADB = \angle ARD + \angle BRD = 120° + 260° = 380° \).

- This exceeds 360°, which suggests an error. Since
\( AD \) and
\( BD \) are parts of the circle that add up to its whole circumference, they should add up to 360°, not more. Hence,
\( ADB \) should be
\( 360° - \angle BCD \) which is 360° - 40° = 320°.

3. Measure of arc
\( ABC \):

- Arc
\( ABC \) includes arcs
\( AB \) and
\( BC \).

-
\( BC \) is opposite the central angle
\( \angle BRC \), which is given as 40°.

-
\( AB \) is the rest of the circle not included in \( ADB \), so
\( AB = 360° - \angle ADB \).

- Since we've found an inconsistency with
\( ADB \), we should instead calculate
\( AB \) as
\( 360° - (BD + CD) = 360° - (260° + 60°) = 40° \).

- Adding \( AB \) and \( BC \), the measure of arc
\( ABC = AB + BC = 40° + 40° = 80° \).

There seems to be an error with the measure of arc
\( ADB \) as calculated before. Arcs
\( AD \) and
\( DB \) should add up to 360° because they complete the circle together. It's also worth noting that in a properly drawn circle, the sum of the measures of arcs
\( BC \),
\( CD \), and
\( DA \)should add up to 360°. If
\( BC \) is 40° and
\( CD \) is 60°, then
\( DA \) should be 360° - (40° + 60°) = 260°, not 120°. This discrepancy suggests there may be a mistake in the given information or a misinterpretation of the diagram.

To summarize, given the information provided:

- The measure of arc
\( BD \) is 260°.

- The measure of arc
\( ADB \) should be 320° (corrected).

- The measure of arc
\( ABC \) is 80°.

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.