Answer: 3, 7 and 14
Explanation:
We want 3 numbers with a mean of 8, and a MAD of 4.
if we have the numbers a, b and c.
The mean is:
M = (a + b + c)/3
MAD = ( Ia - MI + Ib - MI + Ic - MI)/3
now, we know that M = 8 and MAD = 4, so we can replace those values:
8 = (a + b + c)*/3
3*8 = 24 = a + b + c
and
4 = ( Ia - 8I + Ib - 8I + Ic - 8I)/3
4*3 = 12 = Ia - 8I + Ib - 8I + Ic - 8I
So now we have the two equations:
24 = a + b + c
12 = Ia - 8I + Ib - 8I + Ic - 8I
Let's took the numbers 3, 7 and 14
I selected those because are the numbers where the distance between them is the biggest, and they add up to 24, and you can see that the MAD is a big number, which implies that our 3 numbers are not close between them.
3 + 7 + 14 = 10 + 14 = 24
and for the MAD
I3 -8I + I7 - 8I + I14 - 8I = 5 + 1 + 6 = 12
So the correct options are 3, 7 and 14