Answer:
90√2 feet
Explanation:
The geometry of the problem can be modeled by a right triangle with sides 90 feet. The length of the hypotenuse is the distance from home plate to 2nd base. The Pythagorean theorem tells you that distance (c) is ...
c² = a² +b²
c² = (90 ft)² +(90 ft)² = 8100 ft² +8100 ft²
c² = 16200 ft²
c = √16200 ft = 90√2 ft
The distance between home plate and second base is 90√2 feet.