212k views
0 votes

f(x)=16t^2+32tThe function f(x)=-16t^2+32t represents the height of a pumpkin t seconds after it is launched from a catapult. When does the pumpkin reach its maximum height? What is the maximum height of the pumpkin?

User Tkachuko
by
7.0k points

1 Answer

3 votes

Answer:

- time = 1second

- maximum height = 16m

Explanation:

Given the height of a pumpkin t seconds after it is launched from a catapult modelled by the equation

f(t)=-16t²+32t... (1)

The pumpkin reaches its maximum height when the velocity is zero.

Velocity = {d(f(x)}/dt = -32t+32

Since v = 0m/s (at maximum height)

-32t+32 = 0

-32t = -32

t = -32/-32

t = 1sec

The pumpkin reaches its maximum height after 1second.

Maximum height of the pumpkin is gotten by substituting t = 1sec into equation (1)

f(1) = -16(1)²+32(1)

f(1) = -16+32

f(1) = 16m

The maximum height of the pumpkin is 16m

User SlugFiller
by
7.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.