Question

Calculate the specific heat capacity of a new alloy if a 15.4 g sample absorbs 297 Joules when it is heated from 5.0 °C to 20.7 °C. The key assumes you are giving your answer in Joules/g°C and rounding to 2 or 3 sig figs

Answer 1

Answer: The specific heat of alloy is
`1.23J/g^0C`

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat absorbed = 297 J

m= mass of substance = 15.4 g

c = specific heat capacity = ?

Initial temperature =
`T_i` = 5.0°C

Final temperature =
`T_f` =20.7°C

Change in temperature ,
`\Delta T=T_f-T_i=(20.7-5.0)^0C=15.7^0C`

Putting in the values, we get:

`297J=15.4g* c* 15.7^0C`

`c=1.23J/g^0C`

The specific heat of alloy is
`1.23J/g^0C`