202k views
0 votes
Two balloons are charged with an identical quantity and type of charge: -6.25 nanoCoulombs (10-9). They are held apart at a separation distance of 61.7 cm (make sure to use METERS!). Determine the magnitude of the electrical force of repulsion between them.

1 Answer

3 votes

Answer:

force between both the balloons is
9.23* 10^(-7)N

Step-by-step explanation:

It is given charge on both balloons are same and equal to
q=-6.25* 10^(-9)C

Separation between both the balloons
r=61.7cm=0.617m

According to Coulomb's law force between two charges is given by


F=(1)/(4\pi \epsilon _0)(q^2)/(r^2)=(Kq^2)/(r^2)

Therefore force is equal to


F=(9* 10^9* (-6.25* 10^(-9))^2)/(0.617^2)


F=9.23* 10^(-7)N

So force between both the balloons is
9.23* 10^(-7)N

User Siegi
by
4.6k points