Question

Quadrilateral PQRSis graphed in the coordinate plane.

To the nearest tenth, what is the perimeter of quadrilateral PQRS?

Answer 1

Answer:33.7

Explanation:

8+8.5+6+11.2=33.7

Answer 2

33.6

Explanation:

As we can see in the graph, the points:

• P is located at (-2, 8)
• Q is located at ( 6, 8)
• R( is located at (6, 2)
• S is located at (-5, 0)

To find a distance between two points or the length of the segment, we use the following formula:

`√((x2-x1)^2+(y2-y1)^2)`

Because the two points P and Q are located at the same libe y = 8

=> the lenght of PQ =
`\sqrt{(6- (-2))^(2) } = \sqrt{8^(2) } = 8\\`

Because the two points R and Q are located at the same libe x = 6

=> the length of RQ =
`\sqrt{(8-2)^(2) } = \sqrt{6^(2) } = 6\\`

The lenght of RS is:
`√((-5-6)^2+(0-2)^2) = \sqrt{-11^(2) +(-2)^(2) }` =
`√(125) = 11.1`

The lenght of SP is:
`√((-5-(-2))^2+(0-8)^2) = \sqrt{-3^(2) +(-8)^(2) } = √(73)` = 8.5

=> the perimeter of quadrilateral PQRS = PQ+RQ+RS+SP

= 8+6+11.1+8.5

= 33.6