Question

Find the circumference of the larger circle if the area of one of the smaller circles is 48 pi in^2.

A.
`4√(3\pi )` in.
B.
`8√(3 \pi )` in.
C.
`16√(3\pi )`in.
D.
`24\pi` in.

Answer 1

Explanation:

Given two circa inscribed side by side inside a big circle, it is notice that the internal two circle are identical and diameter of the one the internal circles is equal to the radius of the big circle

So, we are given the area of one of the small circle, so from their we can find the radius of the small circle.

Area of small circle

A = 48π in²

Area of a circle is given as πr²

A = πr²

48π = πr²

Divide both side by π

48 = r²

Take Square root of both sides

r = √48 = √(16 × 3)

r = 4√3 in

Then, the diameter of the small circle is

d = 2r = 2 × 4√3

d = 8√3

So, the radius of the big circle is

R = d = 8√3

So, we want to find the perimeter of the big circle

The perimeter of a circle is calculated using

Perimeter = 2πr

P = 2πR

P = 2π × 8√3

P = 16π√3 in

So the correct option is C

P = 16√3 π in.

Answer 2

C. 16√3π in.

Explanation:

Circumference of a circle = 2πr where

r is the radius of the circle.

Given the area of one of the smaller circle to be 48π in², we can get the radius of one of the smaller circle.

If A = πr²

48π = πr²

r² = 48

r = √48 in

The radius of one of the smaller circle is √48.

To get the circumference of the larger circle, we need the radius of the larger circle. The radius R of the larger circle will be equivalent to the diameter (2r) of one of the smaller circle.

R = 2r

R = 2√48 inches

Since C = 2πR

C = 2π(2√48)

C = 4√48π in

C = 4(√16×3)π in

C = 4(4√3)π in

C = 16√3π in

Thw circumference of the larger circle is 16√3π in.