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the sequence {a_n} is defined by a_1= 1 and a_(n+1) = 1/2( a_n+ (4/a_n) ) for >=1. Assuming that {a_n} converges, find its limit.

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a_(n+1)=\frac{a_n+\frac4{a_n}}2

Assuming convergence of the sequence, we have
a_n\to L for some limit
L as
n\to\infty. This also means
a_(n+1)\to L. So in the above equation, we can substitute and solve for
L:


L=\frac{L+\frac4L}2


\implies2L^2=L^2+4


\implies L^2=4\implies L=\pm2

The limit can only be one of these values; otherwise, the sequence would be divergent. To decide which one is correct, we can observe that the sequence is strictly positive. So
L=2.

User DeRagan
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