Question

The circumference of the inner circle is 88 ft. The distance between the inner circle and the outer circle is 3 ft. By how many feet is the circumference of outer circle greater than the circumference of the inner​ circle? Use StartFraction 22 Over 7 EndFraction

for pi. (3.14)

Answer 1

18.9

Explanation:

Answer 2

18.86 feet

Explanation:

The circumference of the inner circle is 88 ft.

Circumference of a Circle
`=2\pi r`

Therefore:

`2\pi r =88\\r=88 / (2*(22)/(7))=14 ft`

Radius of the inner circle=14 feet

If the distance between the inner circle and the outer circle is 3 ft, the radius of the outer circle=14+3 =17 feet.

Therefore. circumference of the outer Circle
`=2\pi r`

`=2*(22)/(7)*17=106.86 ft`

Difference in Circumference=106.86-88 =18.86 feet

The circumference of the outer circle is greater than that of the inner circle by 18.86 feet.