Answer:
Explanation:
Given that,
DE bisects OF, then OB is equal to BF,
So, OB is ½r
Also, DB is equal to BE, so BE = DB = 6 in
So, applying Pythagoras theorem to triangle OBE
OB² + BE² = OE²
(½r)² + 6² = r²
¼r² + 36 = r²
Multiply through by 4
r² + 144 = 4r²
144 = 4r² - r²
144 = 3r²
r² = 144 / 3
r² = 48
r = √48
r = √16×3
r = 4√3 inches
r = 6.93 inches.
So, the radius of the circle is 4√3 inches