Question

Assuming that the tungsten filament of a lightbulb is a blackbody, determine its peak wavelength if its temperature is 3 200 K.

Answer 1

the peak wavelength when the temperature is 3200 K =
`9.05625*10^(-7) \ m`

Step-by-step explanation:

Given that:

the temperature = 3200 K

By applying Wien's displacement law ,we have

`\lambda _m`T = 0.2898×10⁻² m.K

The peak wavelength of the emitted radiation at this temperature is given by

`\lambda _m` =
`(0.2898*10^(-2) m.K)/(3200 K)`

`\lambda _m`=
`9.05625*10^(-7) \ m`

Hence, the peak wavelength when the temperature is 3200 K =
`9.05625*10^(-7) \ m`