Answer:
The arrow is at a height of 48 ft after approximately 0.55 s and after 5.45 s
Explanation:
The following information is missing:
The height of an arrow shot upward can be given by the formula s = v0*t - 16*t², where v0 is the initial velocity and t is time.How long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s?
If the arrow is at a height of 48 ft and its initial velocity is 96 ft/s, then:
48 = 96*t - 16*t²
16*t² - 96*t + 48 = 0
16*(t² - 6*t + 3) = 0
t² - 6*t + 3 = 0
t² - 6*t + 3 + 6 = 0 + 6
t² - 6*t + 9 = 6
(t - 3)² = 6
t - 3 = √6
t - 3 = 2.45; t = 2.45 + 3; t = 5.45
or
t - 3 = -2.45; t = -2.45 + 3; t = 0.55