Question

A circle has a diameter of 11cm

A square has a side length of 7cm

Use pythagoras’ theorem to show that the square will fit inside the circle without touching the edge of the circle.

Pleas help

Answer 1

The diagonal length of the square equals:

diagonal ^ 2 = 7^2 + 7^2

diagonal ^ 2 = 49 + 49

diagonal ^ 2 = 98

diagonal = 9.899 cm

The diagonal is smaller than the circle's diameter and so it will ft inside the circle.

Explanation: