What is the empirical formula of a compound that is 70.62% Hg, 12.48% Cl, and 16.9% O?

asked Sep 6, 2023 25.9k views

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What is the empirical formula of a compound that is 70.62% Hg, 12.48%
Cl, and 16.9% O?

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9 votes

Answer:

Empirical Formula ClHgO3 Mercurous Chlorate

Step-by-step explanation:

Cl=12.48% Hg=70.62% O=16.9%

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