Answer:
(24y^3x-20y^5x^2)/(-3y^5x^2)
= y^3x(24-20y^2x))/(-3y^5x^2)
=(24-20y^2x)/(-3y^2x)
=(24/(-3y^2x))-((20y^2x)/(-3y^2x))
=(-8/y^2x)-(-20/3)
=-8/y^2x + 20/3
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