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What is the empirical formula of a compound that is 41.4% Strontium, 13.24% Nitrogen, and 45.3696 Oxygen ?
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What is the empirical formula of a compound that is 41.4% Strontium, 13.24%

Nitrogen, and 45.3696 Oxygen ?

User Vijay Baskaran
by
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1 Answer

5 votes

Answer:

Empirical Formula N2O6Sr Strontium Nitrate

Step-by-step explanation:

N=13.2% O=45.4% Sr=41.4%

User Rwfbc
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