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What is the area of a triangle whose sides measure 12 inches, 14 inches, and 18 inches?

Enter your answer, in simplified radical form, in the box.

User Nyarasha
by
5.3k points

2 Answers

3 votes

Answer:

8*sqrt(110)

Explanation:

User Jdstaerk
by
5.2k points
5 votes

Answer:

A =
8√(110)
inches^(2)

Explanation:

In this question, we are tasked with calculating the area of a triangle given the length of its three sides

Mathematically, we can calculate this using the Heron's formula

For Heron's formula, A =
√(S(S-A)(S-B)(S-C))

WHERE S =
(A+B+C)/(2)

we take the lengths of the triangle as A,B and C respectively as given

S = (12 + 14 + 18)/2 = 22

Plugging the values into the equation, we have;

A =
√(22(22-12)(22-14)(22-18))\\ \\√(22(10)(8)(4)) \\\\√(7040)

A =
8√(110)
inches^(2)

User Dianne
by
4.9k points