Question

The Wildcats in leopards are on evenly matched football teams when they play there is a .5 probability that the Wildcats win if they play nine times what is the probability that the Wildcats win two of the games round your answer to the nearest 10th of a percent

Answer 1

16.4%

Find nCx (which is 84)

Then find (nCx)(P^x)(Q^n-x), which is (84)(0.5^6)(0.5^3)=0.1640=16.4%

Explanation:

Answer 2

P( x = 2) = 0.4

Or 40%

Explanation:

Given that wildcat has 0.5 probability of winning if they play nine times

Probability = possible outcomes ÷ required outcome

The required outcome = 9

Probability = 0.5

Let calculate the possible outcomes

Possible outcomes = 0.5 × 9 = 4.5 games

the probability that the Wildcats win two of the games will be

P( x = 2) = 2/4.5 = 0.44

Or 44%