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A marshmallow has an initial volume of 0.027 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.205L, what is the pressure inside the chamber?

A marshmallow has an initial volume of 0.027 L at standard pressure (1.0 atm). If the marshmallow is placed in a vacuum chamber and the final volume is 0.205L, what is the pressure inside the chamber?

User ToughMind
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1 Answer

4 votes

Answer:

The pressure inside the chamber is 0.132 atm

Step-by-step explanation:

Step 1: Data given

The initial volume = 0.027 L

The initial pressure = 1.0 atm

The volume changes to 0.205 L

Step 2: Calculate the pressure

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.0 atm

⇒with V1 = the initial volume = 0.027 L

⇒with P2 = the changed pressure = TO BE DETERMINED

⇒with V2 = the changed volume = 0.205 L

1.0 atm *0.027 L = P2*0.205 L

P2 = 0.027/0.205

P2 = 0.132 atm

The pressure inside the chamber is 0.132 atm

User Khalid Khan
by
9.0k points
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