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4 NO(g) + 2 O2(g) = 2 N20468)

User Rohit Ramname
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Answer:

The equilibrium concentrations are [N₂O] = 1.00 mol/L; [O₂] = 0.50 mol/L; [NO] = 1.00 mol/L. Kc = 2.0.

Step-by-step explanation:

First, write the balanced chemical equation with an ICE table.2N₂O + O₂ ⇌ 4NOI/mol·L⁻¹: 0; 0; 3.00C/mol·L⁻¹: +2x; +x; -4xE/mol·L⁻¹: 2x; x; 3.00 - 4xAt equilibrium, [N₂O] = 2x mol/L= 1.00 mol/L.So x = 0.50Then [O₂] = x mol/L = 0.50 mol/Land [NO] = (3.00 - 4x) mol/L = (3.00 – 4×0.50) mol/L = 1.00 mol/LKc=[NO]4[N2O]2[O₂]=1.0041.002×0.50 = 2.0

User ThePrince
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