Question

Partiendo del reposo, un motorista arranca con una aceleración de 2,5 m/s2. ¿Cuál es su velocidad al cabo de 6 s? ¿Qué espacio ha recorrido en ese tiempo?

Answer 1

a) 15m/s

b) 45m

Step-by-step explanation:

a) To find the speed you can use the following formula:

`v=v_o+at`

v: final velocity

v_o: initial velocity = 0m/s

t: time = 6s

a: acceleration = 2.5m/s^2

by replacing the values of v_o, a and t you obtain:

`v=(2.5(m)/(s^2))(6s)=15(m)/(s)`

the velocity is 15m/s

b) To find the distance you use:

`x=v_ot+(1)/(2)at^2=(0)(6)+(1)/(2)(2.5)(6)^2=45m`

the distance is 45m

Answer 2

a)
`v = 15\,(m)/(s)`, b)
`s = 45\,m`

Step-by-step explanation:

a) La velocidad final del motorista es:

`v = 0\,(m)/(s) + \left(2.5\,(m)/(s^(2)) \right) \cdot (6\,s)`

`v = 15\,(m)/(s)`

b) El espacio recorrido por el motorista es:

`s = 0\,m + \left(0\,(m)/(s) \right)\cdot (6\,s) + (1)/(2)\cdot \left(2.5\,(m)/(s^(2)) \right)\cdot (6\,s)^(2)`

`s = 45\,m`