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Math:

Solve the equation. (Enter your answers as a comma-separated list. Use n as an integer constant. Enter your response in radians.)



√(3) \csc x-2 = 0


and


Solve the equation.


cos x + 1 = −cos x


x =

User Natu
by
5.4k points

1 Answer

3 votes

Answer:

a)
x_(1) = (\pi)/(3)\pm 2\pi \cdot i,
\forall i \in \mathbb{N}_(O),
x_(2) = (5\pi)/(6)\pm 2\pi\cdot i,
\forall i \in \mathbb{N}_(O), b)
x_(1) = (\pi)/(3)\pm 2\pi \cdot i,
\forall i \in \mathbb{N}_(O),
x_(2) = (5\pi)/(3)\pm 2\pi\cdot i,
\forall i \in \mathbb{N}_(O)

Explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:


√(3)\cdot \csc x - 2 = 0


√(3) \cdot \left((1)/(\sin x) \right) - 2 = 0


√(3) - 2\cdot \sin x = 0


\sin x = (√(3))/(2)


x = \sin^(-1) (√(3))/(2)

Value of x is contained in the following sets of solutions:


x_(1) = (\pi)/(3)\pm 2\pi \cdot i,
\forall i \in \mathbb{N}_(O)


x_(2) = (5\pi)/(6)\pm 2\pi\cdot i,
\forall i \in \mathbb{N}_(O)

b) The equation must be simplified first:


\cos x + 1 = - \cos x


2\cdot \cos x = -1


\cos x = -(1)/(2)


x = \cos^(-1) \left(-(1)/(2) \right)

Value of x is contained in the following sets of solutions:


x_(1) = (\pi)/(3)\pm 2\pi \cdot i,
\forall i \in \mathbb{N}_(O)


x_(2) = (5\pi)/(3)\pm 2\pi\cdot i,
\forall i \in \mathbb{N}_(O)

User Joseph Lisee
by
5.3k points