Question

NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, in terms of time is given by h=−4.9t2+244t+269.

how high is the rocket after 9 seconds

how high was the rocket when it initially launched

Answer 1

Answer: The height of the rocket after 9 seconds is 2068.1 meters.

The height of the rocket when it initially launched is 269 meters.

Explanation:

Given, NASA launches a rocket at
`t=0` seconds.

Its height, in meters above sea-level, in terms of time is given by
`h=-4.9t^2+244t+269.`

To find, the height of the rocket after 9 seconds put t=9, we get

`h=-4.9(9)^2+244(9)+269\\\\=-4.9(81)+2196+269\\\\=-396.9+2465\\\\=2068.1`

Hence, the height of the rocket after 9 seconds is 2068.1 meters.

To find, the height of the rocket when it initially launched put t=0, we get

`h=-4.9(0)^2+244(0)+269\\\\=0+0+269\\\\=269`

Hence, the height of the rocket when it initially launched is 269 meters.