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Newton’s Law of Cooling expresses the relationship between the temperature of a cooling object y and the time t elapsed since cooling began, in minutes. This relationship is given by y=ae where c is the temperature of the medium surrounding the cooling object, a is the difference between the initial temperature of the object and the surrounding temperature, and k is a constant related to the cooling object. -The initial temperature of a liquid is When it is removed from the heat, the temperature in the room is . For this object, Use Newton’s Law of Cooling to find the temperature of the liquid after 15 minutes.

User Mamut
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2 Answers

6 votes

Answer:

The correct answer is 78.7°F

Explanation:

Got it right on Edge 2020

User JustBoo
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6 votes

Answer:

79 °F

Explanation:

Newton’s Law of Cooling:


y = ae^(-kt) + c

Data

  • The initial temperature of a liquid is 160 °F
  • The temperature in the room (c) is 76 °F
  • Then a = 160 - 76 = 84 °F
  • k = 0.23
  • t = 15 minutes

Replacing into the equation:


y = 84e^(-0.23 * 15) + 76

y = 79 °F

User Solmead
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