Question

Objects 1 and 2 attract each other with a electrostatic force of 18.0 units. If the charge of Object 1 is one-third the original value AND the charge of object 2 is doubled AND the distance then the new electrostatic force will be _____ unit

Answer 1

F'=(8/3)F

Step-by-step explanation:

to find the change in the force you take into account that the electric force is given by:

`F=k(q_1q_2)/((18.0u)^2)=k(q_1q_2)/(324.0)u^2`

However, if q1'=1/3*q, q2'=2*q2 and the distance is halved, that is 18/=9.o unit:

`F'=k(q_1'q_2')/((9u)^2)=k((1/3)q_1(2)q_2)/(81.0u^2)=(2)/(3)k(q_1q_2)/(81.0u^2)`

if you multiply this result by 4 and divide by 4 you get:

`F'=(8)/(3)k(q_1q_2)/(324.0u^2)=(8)/(3)F`

hence, the new force is 8/3 of the previous force F.