Question

2. A packaging box for a

metal rod is 7.5 inches

along a diagonal of the

base. The height of the

box is 18 inches. What

is the length of a

diagonal of the box?

Answer 1

19.5 inches

Step-by-step explanation:

See attachment for the figure, where two diagonals are added with labels.

Given:

length of BC 'b'= 7.5 inches

length of AC 'a'= 18 inches

Required:

length of diagonal= length of BA=?

Also, angle BCA is forming a right angle triangle. So we'll apply the Pythagoras theorem in order to find hypotenuse 'c' i.e the length of BA

c = √a²+b² => √7.5²+18²

c= 19.5

Therefore, the length of a diagonal of the box is 19.5 inches