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16, 10, 5, 7, 13

Based on your sample, what is the average age of the porcupines? What is the standard deviation? Round your

answers to the nearest tenth.

User Tedsmitt
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1 Answer

5 votes

Answer:

Explanation:

Mean = sum of the items in the sample/number of items in the sample

Number of items(ages) = 5

Sum of ages = 16 + 10 + 5 + 7 + 13 = 51

Mean = 51/5 = 10.2

Standard deviation = โˆš(summation(x - mean)/n

Summation(x - mean) = (16 - 10.2)^2 + (10 - 10.2)^2 + (5 - 10.2)^2 + (7 - 10.2)^2 + (13 - 10.2)^2 = 78.8

Standard deviation = โˆš78.8/5

Standard deviation = 4.0 rounded to the nearest tenth

User Eomeroff
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