Question

16. The list below shows the different choices of pizza at

the local pizza shop:
• pepperoni: 11
• supreme: 7
• cheese: 6
• Hawaiian: 3
Based on these results, if 189 pizzas were sold, then how
many could be expected to be cheese?​

Answer 1

Answer: here is a simple answer

Explanation:

6/27 for cheese pizza. Multiply 27 by 7 and 6 by seven. 6x7= 42 27x7= 189. You get 42 to 189.

Answer 2

The expected number of cheese pizza among the 189 pizzas sold is 42.

Explanation:

The distribution of different choices of pizza at the local pizza shop is:

Pizza Frequency

Pepperoni 11

Supreme 7

Cheese 6

Hawaiian 3

_______________

TOTAL 27

Compute the probability of selecting a cheese pizza as follows:

`P(Cheese)=(n(Cheese))/(N)=(6)/(27)=0.222`

Let X = number of cheese pizza sold.

A total of n = 189 pizzas were sold. The probability of selling a cheese pizza is, p = 0.222.

The event of a randomly selected pizza can either cheese or not, is independent of the other pizzas.

The random variable X follows a Binomial distribution with parameters n = 189 and p = 0.222.

The expected value of X is:

`E(X)=np`

Compute the expected number of cheese pizza among the 189 pizzas sold as follows:

`E(X)=np`

`=189* 0.222\\=41.958\\\approx 42`

Thus, the expected number of cheese pizza among the 189 pizzas sold is 42.