Answer:
Option B is correct.
Explanation:
Diagram of given scenario shown below.
Given that,
Diameter of cylinder is
.
Height of cylinder is
.
So, Radius of cylinder is
![= (4)/(2)=2\ mm](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2aihpl3gjvpn21nvbd9t9i73u8ksg04dor.png)
Volume of cylinder =
{where,
,
is the radius
of cylinder and
is height of cylinder}
Substituting the values we get,
Volume of cylinder
![=\pi * (2)^(2)* 8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yt2w5h15zztqdes0x10s7ox4oo47r9xg1r.png)
![=3.14 * 32\\=100.48\ mm^(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/aal08haiqb1ye9lr7hfq0jqwycbc2fdoze.png)
Therefore, Required volume of Cylinder rounding it to the nearest tenth ≈
.
Hence, option B is correct.